Question

can anyone help me please....​

Answer 1

Answer:

Answer:

Step-by-step explanation:

Extend line AB as that meet line DE at " X " , so AX | | CD ( as given AB | | CD  

         and AB is part of AX )

           ∠ CDE = ∠ AXE = 80° --- ( 1 ) ( Corresponding Angles , AX | | CD and DE is  

         transversal line and ∠ CDE = 80° is given )

         Now from angle sum property of triangle we get in triangle BEX :

           ∠ BEX + ∠ AXE + ∠ XBE = 180° , Substitute values , As ∠ BED = ∠ BEX = 40° ,  

         same angles and from equation 1 we get

         40° + 80° + ∠ XBE = 180°

            ∠ XBE = 60° --- ( 2 )

         ∠ XBE + ∠ ABE = 180° ( Linear pair angles )

         60° + ∠ ABE = 180° ( From equation 2 )

        ∠ ABE = 120°