Math, asked by Hari272005, 1 year ago

Can anyone help me?please?

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Answered by nithya312004
3

Answer:

Hi... ✌✌

Here's your answer.... ✔✔

❤Hope it helps you ❤

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Answered by dharshini95
2
let present age of lucky be x years
let present age of lovely be y years
five years ago
lucky's age = x-5
lovely's age = y-5
x-5 = 3(y-5)
x-5 = 3y-15
x-3y+10=0........(1)
ten years later
lucky's age = x+10
lovely's age = y+10
(x+10)= 2(y+10)
x+10= 2y+20
x-2y-20=0.......(2)




x-3y+10=0
x=-10+3y
substituting the value of x in equation (2)
-10+3y-2y-10=0
-10+y-10=0
-10+y=10
y=10+10=20

x=_10+3y
-10+3*20
-10+60
50
the present age of lucky is 50
the present age of lovely is 20

nithya312004: hi...
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