can anyone help me please
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ab = cd let ab be h then ;; in tria. abm -- tan 30 = h/bm → 1/√3 = h/x
√3h = x → h = √3 x / 3
in Δcnd tan 60 = h /15--x → √3 =h/15 -- x → h/√3=15--x → √3x/3×√3 =15--x →
2x = 15 → x = 7.5 m
total distance between two lamp → 7.5+15+7.5 = 30 m
shiny209:
wht does that ---x means?
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