Question

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For class 10​

Answer 1

tanA+cotA=4

(squaring both sides)

(tanA+cotA) 2=4^2

⇒tan 2 A+cot 2 A+2(tanA)(cotA)=16

⇒tan 2 A+cot 2 A+2=16

⇒tan2A+cot2 A=16−2

⇒tan2A+cot 2A=14

(on squaring both sides)

⇒(tan 2 A−cot 2A) 2=(14) 2

tan 4A+cot 4A+2(tan 2 A)(cot 2 A)=196

tan 4A+cot 4A=196−2

=194

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Answer 2

Answer:

194

Step-by-step explanation:

Please see the attached image.

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