Question

can anyone help me right now pls​

Answer 1

$\large \mathtt \color{blue}{Hey~mate~}$

$\large\pink{\sf{20°}}$

$\red{\sf\frak{Explanation~-~}}$

Here AB ll CD, So BD acts as transversal

$\large{\sf{angle~ABD~+~angle~CDB~=~180°~(Co~-~interior)}}$

$\large{\sf{y~+~y~+~2y~+~5y~=~180°~}}$

$\large{\sf{9y~=~180}}$

$\large{\sf{y~=~\frac{180}{9} }}$

$\large{\sf{y~=~20°}}$