Question

Can anyone help me?
$\sqrt[3]{729 } + 3 \frac{3}{5} \div x = \sqrt{16 \times 9}$
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Answer 1

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

$\sf\large \sqrt[3]{729 } + 3 \frac{3}{5} \div x = \sqrt{16 \times 9}$

=>we know that 729 is the cube of 9

e.g,9×9×9=729

and 3⅗ is in mixed fraction so,we have to convert into improper fraction.

=>3⅗=5×3+3/5=15+3/5=18/5

$\sf \longmapsto9 + \dfrac{18}{5} \div x = \sqrt{16 \times 9}$

$\sf \longmapsto \dfrac{45 + 18}{5} \div x = 4 \times 3$

$\sf \longmapsto \dfrac{63}{5} \times \dfrac{1}{x} = 12$

$\sf \longmapsto \dfrac{63}{5x} = 12$

$\sf \longmapsto \: 63 \times 1 = 12 \times 5x$

$\sf \longmapsto60x = 63$

$\sf \longmapsto{ \bold{x = \dfrac{63}{60} }}$

Check

$\sf \longmapsto \dfrac{63}{5} \times \dfrac{1}{x} = 12$

$\sf \longmapsto \dfrac{63}{5} \times \dfrac{1}{ \dfrac{63}{60} }$

$\sf \longmapsto \dfrac{ \cancel{{63}}}{5} \times \dfrac{60}{{ \cancel{63} }}$

$\sf \longmapsto \dfrac{60}{12} = 5$

Answer 2

9+\frac{18}{5}\div x = 4\times3

\frac{18}{5}\div x = 3

\frac{18}{5} \times \frac{1}{x}=3

x = \frac{6}{5}