Math, asked by ssen02369, 1 month ago

can anyone help me to find answer​

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Answered by ssk305805
0

Answer:

It is also given that five years ago, Jacob age was seven times that of his son. Jacob age 5 years ago will be x-5 and that of his son will be y-5. Hence, the present age of Jacob is 40 and that of his son is 10

Answered by llItzDishantll
16

Answer:

LET PRESENT AGE OF JACOB BE 'X' YEARS

LET PRESENT AGE OF HIS SON BE 'Y' YEARS

FIVE YEARS HENCE,

JACOB WILL BE = x + 5 Years

AGE OF HIS SON WILL BE = y + 5 Years

According to the conditions, we get  

y + 5 = 3(x + 5)  

→ 3x - y = -10  .... (1)  

y - 5 = 7(x  - 5)  

7x - y = 30 .... (2)  

Subtracting (1) from (2), we get  

4x = 40 → x = 10  

Substitute the value of x in (1), we get  

y = 3(10) + 10 = 40

Therefore, the present age of Jacob is 40 years and the present age of his Son is 10 years.

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