Question

Can anyone help me to find x and y here​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

∠ DAB + ∠ABC = 180° (co-interior angles are supplementary)

⇒ 3y° + (2y - 5)° = 180°

⇒ 3y° + 2y° - 5° = 180°

⇒ 5y° - 5° = 180°

⇒ 5y° = 185°

⇒ y° = 185°/5°

∴ y° = 37°

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Now, ∠ABC + ∠BCD = 180° (co-interior angles are supplementary)

⇒ (2y - 5)° + (3x + 3)° = 180°

⇒ 2(37)° - 5° + 3x° + 3° = 180°

⇒ 72° + 3x° = 180°

⇒ 3x° = 108°

⇒ x° = 108°/3°

∴ x° = 36°

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