Question

can anyone help me to get this ans. :)​

Answer 1

༒࿐៚ Answer ༒࿐៚

1. AQC

2. APB

3. cpct

Hope it is Correct ✌️

Answer 2

$\bf \huge{Question}$

$\rm \: {In \: the \: adjoining \: figure - }$

$\bf BP \perp \: AC , CQ \perp \: AB \: then \: prove \: that$

$\rm \triangle \: APB \: and \: \triangle \: AQC \: are \: similar$

$\bf{ Solution : }$

$\rm In \: \triangle \: APB \: and \triangle \: AQC$

$\rm \angle \: APB \: = \fbox{90} \degree$

$\rm \angle \: AQC = \fbox{90} \degree$

$\rm \therefore \: \angle\: APB \cong \: \angle \: AQC .... \: from \: (I) \: and \: (II) </p><p>$

$\rm \angle \: PAB \cong \angle \: QAC \: \underline{ \fbox{common \: angle}}$

$\rm\triangle \: APB \: \cong \triangle AQC \: ... \:AA \: test$

_____________________________

$\qquad\qquad\underline{ \underline{ \blacksquare \pmb { \sf \: \red{know \: more : }}}}$

➤ The AA Similarity Theorem states:

If two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.

___________

➽ SSS

• ( Side - Side - Side )

➽ SAS

• ( Side - Angle - Side )

➽ ASA

• ( Angle - Side - Angle )

➽ AAS

• ( Angle - Angle - Side )