Question

can anyone help me to solve this

Answer 1

3x/5 =x-4 =>x=10=>x+5=15

Answer 2

hello,
(7)
let the present age of raman be x
3/5 of his age will be 3x/5
age of raman 4 years ago will (x-4)yrs
according to question,
(3x/5)-(x-4)=0
transpose -(x-4) to other side
∴equation becomes    ⇒3x/5=x-4
⇒3x=5(x-4)
⇒3x=5x-20
⇒5x-3x=20      (-20 will go other side and 3x will come this side)
2x=20
x=20
therefore,raman's present age is 10yrs
after 5 yrs,his age will be 15yrs

(8)
given ratio is 3:4
let the ages of ram and gopal be 3x and 4x
clearly gopal is elder than ram
after 2 yrs gopal will (4x+2)yrs    ram will be (3x+2)
difference of their ages is 10
(4x+2)-(3x+2)=10
4x+2-3x-2=10
4x-3x+2-2=10
x=10
ram's age is 3x=30
gopal's age is 4x=40

(9)
let the length(l) be x m
∴breadth(b) will be 5x/6 m
now,
1 round around the park will be its perimeter(p)
2 rounds will be 2p,here 2p=1540m
p=1540/2=770m=perimeter
perimeter=2(l+b)
770=2(x+5x/6)
770=2(6x+5x)/6
770=11x/3
x=770×3/11
x=70×3
x=210m
∴length of park is 210m
and breadth=5x/6=5×35=175m

(10)
let the unequal side be x m
∴length of equal side=3x/4 m
perimeter=90m
in isosceles triangle,there 2 equal sides and one equal side
perimeter=2(equal side)+unequal side
90=2(3x/4)+x
90=3x/2+x
90=(3x+2x)/2
90=5x/2
x=90/5×2
x=18×2
x=36m
∴length of unequal side is 36m
and length of equal sides is 3x/4=3×36/4=3×9=27m
the dimensions of triangle will be 36m,27m,27m

(11)
let the amount of water added be x
total solution is 25 L and alkali is 15 L
∴remaining will be water that is 10 L is water
when x L of water is added then the solution becomes 30%alkali
which means that solution becomes 70% water
now x L water will be added,new solution will be (25+x) L whose 70% is water
therefore,the equation becomes=
10+x=70% of (25+x)
⇒10+x=70/100×(25+x)
⇒10+x=7/10 × (25+x)
⇒10+x=(175+7x)/10       opening the bracket
⇒100+10x=175+7x
⇒10x-7x=175-100
⇒3x=75
⇒x=25 L
∴water added to the 25 L solution such that alkali becomes 30% is 25 L

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