Question

can anyone help me to solve this question??​

Answer 1

Answer:

45° is the correct answers

Answer 2

Join BP, AP and BQ.

∠BOP = 2∠BAP

Thus, ∠BAP = 60° (Angle formed at the centre is twice that of the angle    formed at the circumference)

∠PAQ = 90° (Angle in inscribed in a semicircle is always 90°)

∠BAP + ∠QAB = 90°

Thus, ∠QAB = 30°