Question

Can anyone help me with answering this question, step by step method please:
A ball dropped vertically falls d metres in t seconds d is directly proportional to the square of t the ball drops 80 meters in the first 4 seconds how far does the ball drop in the next 8 seconds

Answer 1

Answer:

640 m

Step-by-step explanation:

D = kt^2  where d is the constant of proportionality.

D = 80 m when t = 4 seconds so:

80 = k*4^2

k = 80 / 16 = 5.

So the equation of motion is D = 5t^2.

When t = 8+4 = 12 seconds D = 5*12^2 =  5*144

=  720 m

So the distance the ball drops in the next 8 seconds = 720 - 80

= 640 m.

Hope it helps!

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