can anyone help me with this
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Hey
F = 5e4 N ✓✓
m = 3e7 N ✓✓
Now, F = ma
=> a = ( 5/3 ) * 10^(-3) m s^(-2) ✓✓
--> 2as = v^2 - u^2
---> where u = 0 ( since ship was at rest )
=> 2 ( 5/3 )( 3 ) ( 10^(-3) ) = v^2
=> v^2 = 10^(-2)
=> v = 1/10 m s^(-1)
Since, Force is applied for 3m, we take s = 3 ✓✓
Since, a constant acceleration is applied ✓✓
Also, The formula is third law of motion ✓✓
Thus, final speed of ship = 10 cm s^(-1) ✓✓
F = 5e4 N ✓✓
m = 3e7 N ✓✓
Now, F = ma
=> a = ( 5/3 ) * 10^(-3) m s^(-2) ✓✓
--> 2as = v^2 - u^2
---> where u = 0 ( since ship was at rest )
=> 2 ( 5/3 )( 3 ) ( 10^(-3) ) = v^2
=> v^2 = 10^(-2)
=> v = 1/10 m s^(-1)
Since, Force is applied for 3m, we take s = 3 ✓✓
Since, a constant acceleration is applied ✓✓
Also, The formula is third law of motion ✓✓
Thus, final speed of ship = 10 cm s^(-1) ✓✓
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