Question

can anyone help me with this ​

Answer 1

Answer :

We are give that, the ratio of the two adjacent sides of parallelogram are 3:8 and we are also given the perimeter of parallelogram that is 110 cm. And we need to find the sides of parallelogram. So, let's do it :

Let the two adjacent sides of parallelogram be 3x and 8x.

᠂ According to the Question Now :

↠Perimeter of parallelogram = Sum of it's all sides

↠110 = 3x + 8x + 3x + 8x

↠110 = 11x + 11x

↠110 = 22x

↠x = 110 ÷ 22

↠x = 5

◖THE TWO ADJACENT SIDES :

• 3x = 3(5) = 15 cm
• 8x = 8(5) = 40 cm

∴ Length of the sides of parallelogram are 15cm, 40cm , 15 cm and 40 cm.

Answer 2

$\large\underline{ \underline{ \sf \maltese{ \: Correct \: Question:- }}}$

Two adjacent sides of a parallelogram are in the ratio 3:8 and it's perimeter is 110 cm. Find sides of the parallelogram.

$\large\underline{ \underline{ \sf \maltese{ \: To\:Find:- }}}$

Measure of sides AB, BC,CD and DA.

$\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}$

We know that, opposite sides of a parallelogram are equal and we are given that perimeter of the parallelogram is 110cm.

Also it is given that the ratio of adjacent sides is 3:8

Therefore let the measure of the adjacent sides be 3x and 8x.

∴ AD=3x

 AB=8x

 BC=3x

 DC=8x

So According to question,

$\sf{3x+8x+3x+8x=110cm}$

$\sf{\implies}{11x+11x=110}$

$\sf{\implies}{22x=110}$

$\sf{\implies}{x=}{\dfrac{110}{22}}$

$\sf{\implies}{\green{x=5}}$

Therefore, measure of it's sides:

$\sf{\red{AB=8x=8\times 5=40cm}}$

$\sf{\red{BC=3x=3\times 5=15cm}}$

$\sf{\red{DC=8x=8\times 5=40cm}}$

$\sf{\red{AD=3x=3\times 5=15cm}}$

$\large\underline{ \underline{ \sf \maltese{ \:Diagram:- }}}$

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1,1)(1,1)(6,1)\put(0.4,0.5){\bf D}\qbezier(1,1)(1,1)(1.6,4)\put(6.2,0.5){\bf C}\qbezier(1.6,4)(1.6,4)(6.6,4)\put(1,4){\bf A}\qbezier(6,1)(6,1)(6.6,4)\put(6.9,3.8){\bf B}\put(3.3,0.5) {\bf{40cm}} \put(0.1,2.25){\bf{15cm}} \end{picture}$

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