can anyone help me with this prblm ......que. no. 14
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Hey!!!
Assume a common centre O is the two concentric circles.
Draw OL perpendicular to AD
=> OL bisects AD and BC(theorem).
=> AL = LD---------(1)
and
=> BL = LC---------(2)
Subtract (2) from (1).
=> AL - BL = LD - LC
=> AB = CD
HENCE PROVED
Hope this helps you
Assume a common centre O is the two concentric circles.
Draw OL perpendicular to AD
=> OL bisects AD and BC(theorem).
=> AL = LD---------(1)
and
=> BL = LC---------(2)
Subtract (2) from (1).
=> AL - BL = LD - LC
=> AB = CD
HENCE PROVED
Hope this helps you
Aaditiyadav:
Ty
Answered by
1
first join O(centre) to the chord.
now by the theorem "line through the centre bisects the chord" so OE bisects AD as well as BC ..(they are concentric circles)
then,
AE=ED...(1)
BE=EC....(2)
substracting (2) from (1)
AE-BE=ED-EC
AB=CD....hence proved!!n
bruh....!
now by the theorem "line through the centre bisects the chord" so OE bisects AD as well as BC ..(they are concentric circles)
then,
AE=ED...(1)
BE=EC....(2)
substracting (2) from (1)
AE-BE=ED-EC
AB=CD....hence proved!!n
bruh....!
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