Math, asked by anich33, 6 months ago

can anyone help me with this question ​

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Answers

Answered by Aditya916083
0

Answer:

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Answered by Anonymous
4

Answer:

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12

= 12

= 12

= 12

= 12

= 12

= 12

= 12

= 12

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