Question

can anyone help me with this question? Physics is hardd : (

Answer 1

Answer:

(b) Suppose, if the mass of the meter rule be M.

Given, uniform meter rule, so weight (Mg) will act at 25 cm.

Mg produces anticlockwise moment about point o.

Now, in order to balance the 20g weight is tied at 50cm point and it acts in the clockwise direction.

As we know, the principle of moments states that

Anticlockwise moment = Clockwise moment

Mg(29 - 25) = 0.02 g (50-29) \\[0.5em] M = \dfrac{21\times 0.02}{4} \\[0.5em] = 0.105 kg \\[0.5em] = 105gMg(29−25)=0.02g(50−29)

M= 21×0.02/4

=0.105kg

=105g

note:- A is given in the pic attached hope it helps you

Explanation:

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Answer 2

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