can anyone help me with this ? the figure is so confusing .
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Hey I know the answer I tell you the answer see in the question it says that line BA||Ed and BC||EF.ok. So now we produce line DE to intersect line BC. Let the point it intersect is p... Now we can see that EDF are forming z shape so they are alternative angles and they are equal
rshashwat2014:
do u mean LFED?
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