Question

can anyone help please​

Answer 1

Answer:

i) c

ii) a

iii) d

iv) a

v) b

Step-by-step explanation:

i) A= (3, 5); and B= (7, 9)

ii) for any points U of coordinate (Xu, Yu) and V of coordinate (Xv, Yv),

dist uv = $\sqrt{(Xv - Xu)^{2} +{(Yv - Yu)^{2} } }$

⇒ dist AB = $\sqrt{(Xb - Xa)^{2} +{(Yb - Ya)^{2} } }$

                = $\sqrt{(7 - 3)^{2} +{(9 - 5)^{2} } }$

                = $\sqrt{(4)^{2} +{(4)^{2} } }$

                = $\sqrt{(16) +{(16) } }$

                = $\sqrt{32}$ units

iii) equidistant means equal distance from each point ie 4 units from A, 4 units from B, 4 units from C, 4 units from D

and this point is (7, 5)

iv) A = (3, 5); C = (11, 5)  

dist AC = $\sqrt{(Xc - Xa)^{2} +{(Yc - Ya)^{2} } }$

            = $\sqrt{(11 - 3)^{2} +{(5 - 5)^{2} } }$

            = $\sqrt{(8)^{2} +{(0)^{2} } }$

            = $\sqrt{(64) } }$

            = 8 units

v) C = (11, 5) and B = (7, 9)