Question

can anyone help this question please

Answer 1

Answer:

Step-by-step explanation:

The sum of ( 2p² + 3pq - q² ) and ( - p² - pq - q² )

(2p² + 3pq - q² ) + ( - p² - pq - q² )

= ( 2p² - p² ) + ( 3pq - pq ) + ( - q² - q² ) (∵ like terms adding )

= p² + 2pq + ( - 2q² )

= p² + 2pq - 2q² ( ∵ + × - = - )

Now another sum of ( 3p² - q² ) and ( - p² + pq + 4q² )

( 3p² - q² ) + ( - p² + pq + 4q² )

= ( 3p² - p² ) + ( - q² + 4q² ) + ( pq ) ( ∵ like terms adding )

= 2p² + 3q² + pq

Now subtract from ( p² + 2pq - 2q² ) the another sum ( 2p² + 3q² + pq )

( p² - 2q² + 2pq ) - ( 2p² + 3q² + pq )

= ( p² - 2p² ) + ( - 2q² -3q² ) + ( 2pq - pq )

= - p² + ( - 5q² ) + pq

= - p² - 5q² + pq is the answer..