Math, asked by deep2000, 1 year ago

Can anyone just help me out with this. Would be thankful !

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Answered by BEJOICE
1

 \int \frac{2 {x}^{2} + 3 }{( {x}^{2} - 1)( {x}^{2}  + 4) }   \\  =  \int \frac{1 }{( {x}^{2} - 1)}   +  \int \frac{1 }{( {x}^{2}  + 4) }  \\  =    \int \frac{1 }{(x + 1)( x- 1)}   +  \int \frac{1 }{( {x}^{2}  +  {2}^{2} ) }  \\  = \frac{1}{2}  \int (\frac{1 }{( x- 1)}  -  \frac{1 }{(x + 1)} ) +  \frac{1}{2} \int \frac{2 }{( {x}^{2}  +  {2}^{2} ) }\\  =  \frac{1}{2} ( ln(x - 1)  -  ln((x + 1))  +  \frac{1}{2}    {\tan}^{ - 1} ( \frac{x}{2} )  \\  =   \frac{1}{2} ln( \frac{x - 1}{x + 1} )  + \frac{1}{2}    {\tan}^{ - 1} ( \frac{x}{2} ) + c \\ comparing \:  \: a = \frac{1}{2}  \:  \: and \:  \: b =  \frac{1}{2}  \\
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