Question

can anyone kindly answer ascending and descending order of fraction...that is given above I will be grateful...

please please all... help!!!
it's homework ​

Answer 1

Answer:

(9) Ascending Order

(a) LCM of denominators = 36

$\frac{2}{3}$ × $\frac{12}{12} = \frac{24}{36}$

$\frac{5}{6}$ × $\frac{6}{6} = \frac{30}{36}$

$\frac{8}{9}$ × $\frac{4}{4} =\frac{32}{36}$

$\frac{11}{12}$ × $\frac{3}{3} = \frac{33}{36}$

$\frac{17}{18}$ × $\frac{2}{2} = \frac{34}{36}$

$\frac{24}{36} <\frac{30}{36} <\frac{32}{36} <\frac{33}{36} <\frac{34}{36}$

Hence, ascending order is $\frac{2}{3}$ < $\frac{5}{6}$ < $\frac{8}{9}$ < $\frac{11}{12}$ < $\frac{17}{18}$

(b) LCM of denominators = 24

$\frac{1}{4}$ × $\frac{6}{6}= \frac{6}{24}$

$\frac{5}{6}$ × $\frac{4}{4} = \frac{20}{24}$

$\frac{5}{8}$ × $\frac{3}{3} = \frac{15}{24}$

$\frac{7}{12}$ × $\frac{2}{2} =\frac{14}{24}$

$\frac{1}{2}$ × $\frac{12}{12} =\frac{12}{24}$

$\frac{6}{24} < \frac{12}{24} <\frac{14}{24} <\frac{15}{24} <\frac{20}{24}$

Hence ascending order is $\frac{1}{4} < \frac{1}{2} < \frac{7}{12} <\frac{5}{8} <\frac{5}{6}$

(10) Descending Order.

(a) LCM of denominators = 40

$\frac{3}{5}$ × $\frac{8}{8} = \frac{24}{40}$

$\frac{7}{10}$ × $\frac{4}{4} =\frac{28}{40}$

$\frac{13}{20}$ × $\frac{2}{2} = \frac{26}{40}$

$\frac{11}{40}$ × $\frac{1}{1} = \frac{11}{40}$

$\frac{28}{40} >\frac{26}{40} >\frac{24}{40} >\frac{11}{40}$

Hence descending order is $\frac{7}{10}$ > $\frac{13}{20}$ > $\frac{3}{5}$ > $\frac{11}{40}$

(b) LCM of denominators = 63

$\frac{4}{9}$ × $\frac{7}{7} = \frac{28}{63}$

$\frac{1}{21}$ × $\frac{3}{3} = \frac{3}{63}$

$\frac{5}{7}$ × $\frac{9}{9} = \frac{45}{63}$

$\frac{11}{63}$ × $\frac{1}{1}=\frac{11}{63}$

$\frac{45}{63} > \frac{28}{63} >\frac{11}{63} >\frac{3}{63}$

The descending order is $\frac{5}{7}$ > $\frac{4}{9}$ > $\frac{11}{63}$ > $\frac{1}{21}$

Hope it helps