Can anyone make the redox equation of this reacion.I also need to see the two half reaxtions (oxidaion and reduction).
FeS2+O2----Fe2O3+SO2
please answer fasttttt.THE fastest answer will be marked as the brainly
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Correct equation for the above mentioned reaction is:
FeS + O2 → Fe2O3 + SO2
In this reaction:
Sulphur (S) oxidized from “-2” charge to “+4” charge.
Iron (Fe) is oxidized from “+2” charge to “+3” charge.
Oxygen reduced from “0” charge to “-2” charge.
This reaction can be balanced in simpler manner (balancing each atom on either sides of the equation).
4FeS + 7O2 → 2Fe2O3 + 4SO2
margarita:
excuse me..........its is fes2 and not fe...........plus that i think it is like this way.............
like this..............8 S-I - 40 e- → 8 SIV (oxidation)
4 FeII - 4 e- → 4 FeIII (oxidation)
22 O0 + 44 e- → 22 O-II (reduction)
Change the oxidation states
4 FeII - 4 e- → 4 FeIII (oxidation)
22 O0 + 44 e- → 22 O-II (reduction)
Change the oxidation states
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