can anyone of class 12 solve the problem
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1
Step-by-step explanation:
log392−−−√
=12log392
=12log(72×23)
=12(log72+log23)
=12(2log7+3log2)
=x+3/2y
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Answer:
I am in class 8 so 4 years later I will tell you this question,s answer
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