Math, asked by sara32, 1 year ago


can anyone please answer my question its very urgent.

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Answered by Anonymous
1
4a²-9b²-(2a-3b)
(4a²-9b²)-(2a-3b)
[(2a)²-(3b)²]-(2a-3b)
a²-b² = (a+b)(a-b)
(2a-3b)(2a+3b) - (2a-3b)

taking (2a-3b) common
(2a-3b)(2a+3b-1)

a²+b²-2(ab-ac+bc)
a²+b²-2ab+2ac-2bc
(a²+b²-2ab) + (2ac-2bc)

a²+b²-2ab => (a-b)²

(a-b)² + 2c(a-b)
taking (a-b) common

(a-b)(a-b+2c)

hope this helps
any confusion then message me
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