Question

Can anyone please answer this​

Answer 1

Answer:

The ‘value of c’ is \bold{{0.11}} for the given unit vector.

Explanation:

We have been given a unit vector which is represented as 0.5 {i}+0.8 {j}+{ck}. A vector has ‘magnitude of one’.  

Hence, we can say that  |a+b+c|=1 {0.5}^{2}+{0.8}^{2}+{c}^{2}=1

Squaring both sides  

(0.5)^{2}+(0.8)^{2}+(c)^{2}=10.25+0.64+c^{2}=1c^{2}+0.89=1.00c^{2}=0.11\bold{c=

{0.11}}

ANS ={0.11}}