Question

can anyone please answer this questions plzz

Answer 1

i know ans fr 2nd one
and the value of k is 0

hope it hlps u

Answer 2

If these point are colliner, you just have to find area because by knowing area we can judge whether a line is colliner or not

we have points (2,3) (4,k) and (6,-3)

so, Area = 1/2 |2k-12+18-(12+6k-6)|
= 1/2 |2k-12+18-12-6k+6|
= 1/2 |-4k|
And since we know that, it is a colliner therefore
1/2|-4k| = 0
4k=0
k=0 ans