Question

Can anyone please do this.

Answer 1

Step-by-step explanation:

$\frac{4}{3 \sqrt{3} - 2 \sqrt{2} } + \frac{3}{3 \sqrt{3} + 2 \sqrt{2}} = >$

$\frac{4(3 \sqrt{3} + 2 \sqrt{2}) + 3(3 \sqrt{3} - 2 \sqrt{2} )}{(3 \sqrt{3} - 2 \sqrt{2})(3 \sqrt{3} + 2 \sqrt{2}) } = >$

$\frac{12 \sqrt{3} + 8 \sqrt{2} + 9 \sqrt{3} - 6 \sqrt{2}}{27 - 8} = > \frac{21 \sqrt{3} + 2 \sqrt{2}}{19} = >$

$\frac{21(1.732) + 2(1.414)}{19} = > \frac{36.352 + 2.828}{19} = >$

$\frac{39.18}{19} = > 2.0621$

Hope it helps you.

Answer 2

Answer:

answer is in the attachment

Step-by-step explanation:

hope it helps you ☺️☺️

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