can anyone please explain the steps of the answer ....
Ques: if m times the mth term of an AP is equal to n times the nth term show that (m+n)th term of the AP is zero
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here is an attachment
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poojakumaresh26:
in the 6 th step is it (m+n)(m-n) or (am+n)(m-n)?!
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•We simplified the {m}^{th} and {n}^{th} term of the AP and then make an eqn. saying {m}^{th}-{n}^{th}=0.
•simplifying the equation, we take a(m-n) as common and d on the other side.
• Again we simplified and grouped the {.....}d part.
•Now, we take out the (m-n) term common from both the equation and get a+(m+n-1)d that is equal to term m+n.
☺️
•We simplified the {m}^{th} and {n}^{th} term of the AP and then make an eqn. saying {m}^{th}-{n}^{th}=0.
•simplifying the equation, we take a(m-n) as common and d on the other side.
• Again we simplified and grouped the {.....}d part.
•Now, we take out the (m-n) term common from both the equation and get a+(m+n-1)d that is equal to term m+n.
☺️
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