Question

can anyone please give me the answer of this question please....

Answer 1

Heres your answer

We are given a=20 m sec^2

t=10 s

u=0

First we will find v by equation 1 st

v=u+at

v=(0)+(20×10)

v= 200 m sec

So distance will be

$s = ut + \frac{1}{2} a {t}^{2} \\ \\ s = (0 \times 10) + \frac{1}{2} \times 20 \times 100 \\ \\ s = 1000$
Hope it Helps!!