Can anyone please help me to solve the following equation
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Answer: a= 11 and b= 6
Step-by-step explanation:
q. [5+2√3] / 7+4√3
Rationalising the denominator
= (5+2√3) (7-4√3) / (7+4√3) (7-4√3)
(35 - 20√3 + 14√3 - 8(√3)(√3) / 49 - 48
as (a+b)(a-b) = a^2 + b^2
Simplifying
35 - 24 - 20√3 + 14√3 /1
= 11 - 6√3
so, 11 - 6√3 = a - b√3
by comparing both of the 2 sides
a = 11 and b = 6
Thanks for asking help
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