Question

can anyone please help me with the 10th question.the best answer will be marked as brainliest.

e65c21b327fcdfa7654ec01336c42993.docx

Answer 1

p(x)=x3+2x2−5ax−7

Since p(x) is divisible by (x+1) the remainder is p(−1)

p(−1)=−1+2+5a−7

=5a−6

=A

Step 2:

t(x)=x3+ax2−12x+6

Since t(x) is divisible by (x−2) the remainder is t(2)

t(2)=(2)3+4a−24+6

=4a−10

=B

Step 3:

Since 2A+B=6

we know that A=(5a−6),B=4a−10

Therefore 2A+B=6⇒2(5a−6)+4a−10=6

Solving for ′a′

10a−12+4a−10=6

14a−22=6

14a=28

We get a=2

hope this helps...