can anyone please help me with this??
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since, PS bisects angle QPR
therefore, angle 1 = angle 2
again, since PR>PQ
=> angle 3 > angle 4 ( angles opp. to longer side is larger)
=> 3 + 1 > 4 +1 ( adding angle 1 on both side)
=> 3+ 1 > 4 + 2 ( angle 1 = angle 2)
=> 5 > 6 ( exterior angle property)
=> angle PSR > angle PSQ.
proved
question no. 5
therefore, angle 1 = angle 2
again, since PR>PQ
=> angle 3 > angle 4 ( angles opp. to longer side is larger)
=> 3 + 1 > 4 +1 ( adding angle 1 on both side)
=> 3+ 1 > 4 + 2 ( angle 1 = angle 2)
=> 5 > 6 ( exterior angle property)
=> angle PSR > angle PSQ.
proved
question no. 5
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