can anyone please say what will be the answer of (-5)+(-5).......upto 100
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The sum of 5+10+15 ….+100 is the sum of an AP whose first terms is 5, the last term is 100 and the common difference is 5.
Th = 100 = a +(n-1)d = 5 +(n-1)5 = 5
Sn = (n/2)[2a+(n-1)d]
= (20/2)[2*5+ (20–1)*5]
= 10[10+95]
= 10*105
= 1050
Step-by-step explanation:
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