Question

Can anyone please solve above question with proper steps?

Answer 1

The density at the surface of water=ρ=MVor V=MρSimilarly the volume at the depth=V'=Mρ'=M1.01ρThe change in volume=∆V=V−V'=Mρ−Mρ'=1101×MρBulk's Modulas=K=1Compressivility=150×10−11So K=PV∆Vor 150×10−11=P×M×101ρρ×M=101P1or P=100×10950×101=0.019×109pascalNow P=hρ'gSo h=Pρ'g=0.019×109101ρ×10=0.019×109101×100×10=19101×103mor h=0.188×103m=0.188Km

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