can anyone please solve this...
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JinKazama1:
Is Option C) 46 is answer?
okay
how
Is this correct?
yes it is but how
??
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Final Answer: 46%
Understanding :
1) By Haley and Smith formula,
Percentage ionic character, =
(0.16D + 0.035D^2) * 100 %
= (16D + 3.5D ^2)%
where D is Electronegativity difference between A and B
Steps:
1) Using above formula,
D = 2.0
Percentage ionic character = 16* 2 +(3.5)*2^2
=32+(3.5)*4
=32+14 = 46%
So, If Electronegativity difference between A and B is 2.0 , then percent ionic character is 46%.
Understanding :
1) By Haley and Smith formula,
Percentage ionic character, =
(0.16D + 0.035D^2) * 100 %
= (16D + 3.5D ^2)%
where D is Electronegativity difference between A and B
Steps:
1) Using above formula,
D = 2.0
Percentage ionic character = 16* 2 +(3.5)*2^2
=32+(3.5)*4
=32+14 = 46%
So, If Electronegativity difference between A and B is 2.0 , then percent ionic character is 46%.
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