can anyone please solve this...
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Sugar being a non volatile solute will lower the vapor pressure of water.
(Po - P)/Po = x2
where x2 is mole fraction of solute
Po is vapour pressure of pure water
P is vapour pressure of solution
n2 = (34.2/342) = 0.1
n1 = 90/18 = 5
x2= 0.1/(0.1+5) = 0.019
Po = 760mmHg, vapour pressure of pure water
On substituting the values,
P = 745.09 mmHg
option D is appropriate answer
(Po - P)/Po = x2
where x2 is mole fraction of solute
Po is vapour pressure of pure water
P is vapour pressure of solution
n2 = (34.2/342) = 0.1
n1 = 90/18 = 5
x2= 0.1/(0.1+5) = 0.019
Po = 760mmHg, vapour pressure of pure water
On substituting the values,
P = 745.09 mmHg
option D is appropriate answer
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