can anyone please solve this...
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For formation of CO2 Equation 2 will have to be reversed making ΔH2 positive.
ΔH2 is for formation of 2 mole CO
but we need to calculate ΔH for formation of 1 mole CO so we need to divide it by 2.
so, ΔH = ΔH1 + Δ H2 / 2
ΔH = -394 + 569/2 = -109.5 KJ mol^-1
ΔH2 is for formation of 2 mole CO
but we need to calculate ΔH for formation of 1 mole CO so we need to divide it by 2.
so, ΔH = ΔH1 + Δ H2 / 2
ΔH = -394 + 569/2 = -109.5 KJ mol^-1
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