can anyone please solve this...
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According to Faraday's second law
nF = Q deposits equivalent mass of a substance, where F = 96500C/mol
In case of AgNO3, n=1, thus
If 96500C deposits 108 g of silver,
then 2.7g will be deposited by
96500*2.7/108 = 2412.5C
nF = Q deposits equivalent mass of a substance, where F = 96500C/mol
In case of AgNO3, n=1, thus
If 96500C deposits 108 g of silver,
then 2.7g will be deposited by
96500*2.7/108 = 2412.5C
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