Question

can anyone please solve this ​

Answer 1

a@b = a*(a+b)²

= a*a²+b+2ab

= a³+b+2ab

so putting a = 1 b = 2

so 1@2 = 1³+2²+2(2)

= 1+4+4= 9

so 9@3= 9³+3²+2(3)(9)

= 729+9+54

=792

so (1@2)@3 = 792

but it is not in the option so please check