Hindi, asked by keshriaryan43, 1 year ago

can anyone please solve this fast as possible

Attachments:

Answers

Answered by ItzAditt007
1

{\huge{\pink{\underline{\underline{\purple{\mathbb{\bold{\mathcal{AnSwEr..}}}}}}}}}

{\large{\blue{\bold{\underline{Given:-}}}}}

\sf\implies \: p(x) =  {x}^{2} - mx + n

\sf\implies \alpha   \: \: and  \: \: \beta  \: zeroes  \: of \: p(x)

{\large{\blue{\bold{\underline{To find:-}}}}}

▪︎ Value of,

\sf\implies \frac{ \alpha }{ \beta }  +  \frac{ \beta }{ \alpha }

{\large{\blue{\bold{\underline{ID\:Used:-}}}}}

\sf\implies {a}^{2}  +   {b}^{2}  = (a + b) {}^{2} - 2ab.

{\large{\blue{\bold{\underline{Now,}}}}}

\sf \: in \: p(x) \frac{.}{.}  -  \\  \\\implies \alpha  +  \beta  =   \frac{ - b}{a} \\  \\   \implies \alpha +  \beta  =   \frac{ - ( - m)}{1}  \\  \\ \implies \alpha +   \beta  =  m   \:  \: ....eq(1) \\  \\ and \\  \\ \implies \alpha  \times b =  \frac{c}{a}   \\  \\ \implies \alpha  \beta  =  \frac{n}{1}  \\  \\ \implies \alpha  \beta  = n \:  \: ...eq(2)

{\large{\blue{\bold{\underline{Therefore:-}}}}}

\sf\implies \frac{ \alpha }{ \beta }  +  \frac{ \beta }{ \alpha }  \\  \\  =  \frac{ { \alpha }^{2} +  { \beta }^{2}  }{ \alpha  \beta }  \\  \\  =  \frac{( \alpha  +  \beta ) {}^{2} - 2 \alpha  \beta  }{ \alpha  \beta }  \\  \\  =  \frac{( {m})^{2}  - 2(n)}{n}  \\ \\  (from \: (1) \: and \: (2)) \\  \\  =   \frac{ {m}^{2} - 2n }{n}

{\small{\green{\boxed{\boxed{\bold{Answer\:=\:m\:square-2n/n.}}}}}}

Hope this will help you if it HELPS then plz mark my answer as BRAINLIEST.

And remember to always keep a smile on face:D

 <marquee \: behaviour = alternate><font \: color =red>✌✌THANKS✌✌

Similar questions