can anyone please solve this trigonometry question
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Answer:
LHS = cos^2 x + tan ^2 x - 1/sin^2 x
= tan^2 x - (1-cos^2 x) / sin^2 x
= tan^2 x - sin^2 x / sin^2 x
= tan^2 x / sin^2 x. - 1
= sin^2 x/ cos^2 x sin^2 x - 1
= 1/cos^2 x - 1
= sec^2 x - 1
= tan^2 x
= RHS
LHS = RHS
Hence proved.
Hope this helps you !
Answered by
0
Answer:
LHS = cos^2 x + tan ^2 x - 1/sin^2 x
= tan^2 x - (1-cos^2 x) / sin^2 x
= tan^2 x - sin^2 x / sin^2 x
= tan^2 x / sin^2 x. - 1
= sin^2 x/ cos^2 x sin^2 x - 1
= 1/cos^2 x - 1
= sec^2 x - 1
= tan^2 x
= RHS
LHS = RHS
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