Question

can anyone please tell how the value of i1 and i2 is calculated in the attachment please dont you coz its serious
class 12 current electricity chapter please help ​

Answer 1

Consider a Potential Difference of V is applied at both the ends of given circuit and a current of I ampere flows through it.

This implies that,

$= > \: V_{a} = V_{b}$

(Potential at A = Potential at B)

Also, by Ohm's Law, we can say :

$V_{ab} = I.R_{eq} \: \: ....(i)$

Now consider a part of the circuit which has r1 resistor,

Let the potential difference across it's ends be V1 and current flowing through it be i1

Therefore, We can say, By Ohm's law that

$v_{1} = i_{1}. r_{1} \: \: ...(ii)$

Now, considering another part of the circuit which has r2 resistor,

Let it's potential difference be V2 and current i2, then

$v_{2} = i_{2}. r_{2} \: \: ....(iii)$

But, We know that the total Potential of

the circuit remains the same across it's

two ends.

Therefore,

$V_{ab} = v_{1} + v_{2}$

From (i), (ii) and (iii) we can write that :

$I.R_{eq} = i_{1}.r_{1} + i_{2}.r_{2}$

Answer 2

Answer:

okkkkkkkkk no problem ...........,.........