Question

Can anyone please tell me the derivation of the given formula of motion :


Average Velocity = (v+u)/2... I am a student of class 9th​

Answer 1

Answer:

Explanation:

If 'u' is the initial velocity of an object, 'v' is the final velocity attained by the object after 't' seconds of time, then acceleration 'a' is given by: a = Change in velocity/Time taken. a = (Final velocity - Initial velocity)/Time taken. a = (v-u)/t. at = (v-u)‍✈️(❁´◡`❁)(●'◡'●)

Answer 2

Answer:

From 3rd equation of motion----

V^2 - u^2 = 2as

s = (V^2 - u^2)/2a

s = (v+u)(v-u) /2a.......1

From 1st equation of motion------

v = u+at

a = v-u/t........2

Now,

Average Velocity = Total displacement / Total time

Vav = s/t

Vav = (v+u)(v-u) /2a /t

= (v+u)(v-u) /2* (v-u) /t/t

= (v+u)/2/1

Vav = (v+u)/2

HENCE PROVED.

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