Question

can anyone please tell me what do we get when we factorize the following polynomial.
(4a-b+2c)^2


IIThxII

Answer 1

Answer:

Step-by-step explanation:

$(a+b+c)^{2} = a^{2} +b^{2} + c^{2} + 2ab + 2bc + 2ca$

$(4a)^{2} + (-b)^{2} + (2c)^{2} = 16a^{2} + b^{2} + 2c^{2} -8ab -2bc + 8ac$