Question

can anyone pls ans this que​

Answer 1

Answer:

Step-by-step explanation:

u=3 m/s and a=2 m/s²

Distance in 4 sec

S4=3*4+1/2*2*(4)²=12+16=28 m

S3=3*3+1/2*2*(3)²=9+9=18 m

Thus distance traveled in 4th sec

=S4-S3 =28-18=10 m

Option(A)

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Q2

v=0,s=80m,g=-10 m/s²,u=?

We know that

v²=u²+2gh

0=u²-2*10*80

u²=1600=40²

u=40 m/s

option(A)