Can anyone pls answer this!!!! With explanation!!!???
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See the molar mass of all of is 102 gm per mole, and by the eqn, (Al2o3=2al3+ +3O2-,we get that one molecule al203 contains 2 Al ion, so divide (. 051/102)=.0005 mole of al203 molecule present, so just multiply twice(. 0005*2) or. 001 mole of alumnium ions present.
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the molar mass of all of its is 102gm per mole,and by the eqn,(AI20o3:2al3+3O2-,we get that one molecule all203 contains 2AI ion ,so divide(.051/102)-0005 mole of al203 molecule present,so multiply twice
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