Question

Can anyone pls say me the 69th answer???

Answer 1

the and is root 6a cm

Answer 2

Hi there !

Let the Length of diagonals be x, y cm respectively .

Given area of square = 2* Area of Rhombus

Also , Side of square = Side of rhombus = a

So,

Area of the square = side² = a^2

Area of Rhombus = xy/2 = 2a²

xy = 4a²

In rhombus,

(side)² = (diagonal)² +  (diagonal)²

a² = (x/2)² + (y/2)²

= (x²+y²) /4

4a^2 = (x+y)^2 - 2xy

4a^2 = (x+y)^2 - 2(4a² )

4a^2 + 8a^2 = (x+y)^2

12a^2 = (x+y)^2

√(12a^2) = (x+y)

3√2a = x+ y

Therefore , Sum of the diagonals of the Rhombus is 3√2a cm .

Correct option is 4