Question

Can anyone pls say the solution of Q2, a and b. Pls use step by step explanation.

Answer 1

$\huge\star{\green{\underline{\mathfrak{Answer!!}}}}$

$\sf\pink{Question\:2 }$

$\sf\pink{solution\:of\:(a)}$

area of tri.ABC = 1/2 ×BC × AE

= 1/2 ×BC × AE = 1/2 × 9 × 4

= 1/2 ×BC × AE = 1/2 × 9 × 4= 18cm^2

$\sf\pink{solution\:of\:(b)}$

area of tri.AEC= 1/2 ×BC × AE

= 1/2 ×BC × AE = 1/2 × 9 × 4

= 1/2 ×BC × AE = 1/2 × 9 × 4= 18cm^2

$\sf\pink{@itz\:theoptimusprime}$