Can anyone pls solve the above attached q pls.
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Answer:(ACCELERATION-3g/7)
(TENSION-20g/7)
Explanation:
IN BOTH STRINGS TENSON IS SAME SO
TENSION IN 2g IS T=2(g+a)--->as it is going up
5g IS T=5(g-a)----->AS IT IS GOING DOWN
SO NOW TENSIONS ARE EQUAL IN TWO STRINGS
2(g+a)=5(g-a)==>2g+2a=5g-5a
===>3g=7a==>a=3g/7 (ACCELERATION)
T=2(g+a)=2(g+3g/7)=20g/7(TENSION)
HOPE YOU UNDERSTOOD.................
THANK YOU.
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